38 votes
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"Cute" applications of the étale fundamental group

Using the étale fundamental group one can construct an injective group homomorphism $\operatorname{Gal}(\overline{\mathbb{Q}}/\mathbb{Q}) \hookrightarrow \operatorname{Out}(\widehat{F_2})$ which is ...
user175608's user avatar
27 votes
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Steenrod operations in etale cohomology?

You maybe want to have a look at P. Brosnan and R. Joshua. Comparison of motivic and simplicial operations in mod-$\ell$ motivic and étale cohomology. In: Feynman amplitudes, periods and motives, ...
Matthias Wendt's user avatar
23 votes
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Why do we care about the eigenvalues of the Frobenius map?

The Riemann hypothesis is very important for the relationship between the cohomology and combinatorics of the variety. First, the Riemann hypothesis lets us read off the Betti numbers from the point ...
Will Sawin's user avatar
  • 131k
22 votes

What is known about the cohomological dimension of algebraic number fields?

By definition, an algebraic number field is a finite extension of the field of rational numbers $\Bbb Q$. An algebraic number field $K$ is called totally imaginary if it has no embeddings into $\...
Mikhail Borovoi's user avatar
22 votes
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When (or why) is a six-functor formalism enough?

When defining a homotopy-coherent structure, you have to strike the correct balance between supplying enough data (so that all isomorphisms (between isomorphisms, ...) that you need later are actually ...
Peter Scholze's user avatar
20 votes

Clarifying the connection between 'etale locally' and 'formally locally'

For local noetherian rings, the henselization has much more direct algebro-geometric meaning than the completion since it is built from local-etale algebras. Hence, your statement that the completion ...
20 votes

Why do we care about the eigenvalues of the Frobenius map?

Here are a few different uses of knowing how large the eigenvalues are as complex numbers. Application 1: Bounding exponential sums. Many classical exponential sums can be interpreted essentially as a ...
KConrad's user avatar
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18 votes

Steenrod operations in etale cohomology?

Your first map fits in an action of the Steenrod algebra. In fact $H^*_{ét}(X;\mathbb{F}_2)$ is the homology of $C^*_{ét}(X;\mathbb{F}_2)=R\Gamma(X;\mathbb{F}_2)$, an element of the derived category ...
Denis Nardin's user avatar
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18 votes
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A short proof for simple connectedness of the projective line

You can deduce this from the classification of vector bundles on $\mathbf{P}^1$. Say $f:C \to \mathbf{P}^1$ is a connected finite etale Galois cover of degree $n$. We must show $n=1$. The sheaf $E := ...
user117273's user avatar
16 votes

Is there a "universal" cohomology theory for varieties over p-adic fields?

I'm seeing this old question just now, and simply wanted to remark that the situation may be slightly better. Namely, enlarging the category of $\mathbb Q$-vector spaces into the larger semisimple $\...
Peter Scholze's user avatar
16 votes
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Tate twists and cohomology of $\mathbf{P}^1$

The Tate twist is what we need to express Poincaré duality without making any choice. Such a choice appears in the choice of an orientation of the affine line minus the origin, and have shadows in the ...
D.-C. Cisinski's user avatar
16 votes
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Commutative algebra counterexample

Let $R=\mathbb{Z}$ and let $M=\mathbb{Z}$ with $x$ acting by $2$. Then $M\otimes_{R[x]}R[x,x^{-1}]\cong \mathbb{Z}[1/2]$ is not finitely generated over $R$.
Eric Wofsey's user avatar
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16 votes
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Étale cohomology of morphism whose fibers are vector spaces

The answer below is slightly reorganized to incorporate the edits. I thank @PiotrAchinger and @S.D. for their comments correcting and clarifying this answer. Definition 1. An affine space morphism ...
15 votes
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Etale cohomology of localizations of henselian rings

TL;DR: Your expectation is right. In fact, there is a third object to compare with $R[1/p]$ and $\hat R[1/p]$, the affinoid rigid space ${\rm Spf}(\hat R)^{\rm rig}$. The cohomology comparison is ...
Piotr Achinger's user avatar
15 votes
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Is there a ring stacky approach to $\ell$-adic or rigid cohomology?

This is an interesting question. First, I think the [PS] reference does not give the "correct" Betti stack. In my notes on 6 functors, I define a different stack $X_B$ such that $D_{\mathrm{...
Peter Scholze's user avatar
14 votes
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Etale cohomology of $\mathrm{Spec}(k\{X,Y\})\backslash\langle0,0\rangle$

I'm not sure what "easy" means in the context of etale cohomology but there is a way of passing from Artin's result to the stated one. Let $j$ from $\mathbb A^2 \backslash \langle 0,0\rangle$ to to $\...
Will Sawin's user avatar
  • 131k
14 votes
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Hodge standard conjecture for étale cohomology

I'm very interested myself on a better answer to this question, but let me point out the obvious: the main problem is that there is no Hodge theory on positive characteristic. The proof in ...
Myshkin's user avatar
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14 votes
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Etale cohomology can not be computed by Cech

Let $k$ be an algebraically closed field. Glue two copies of $\text{Spec}(k[[x]])$ along $\text{Spec}(k((x)))$. This gives a scheme $X = U \cup V$ such that any etale covering of $X$ can be refined by ...
komodo's user avatar
  • 156
14 votes
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Etale cohomology with coefficients in $\mathbb{Q}$

The following is surely expressing whatever is in the core non-formal aspect of Joe Berner's answer (which is above my pay grade); it is offered as an alternative version of the same ideas. Let $X$ ...
14 votes

"Cute" applications of the étale fundamental group

I think a fantastic application of the étale fundamental group is in extensions of the Chabauty-Coleman(-Kim) method. The original idea was that we could bound the rational points on a curve $C$ by ...
Asvin's user avatar
  • 7,498
14 votes

Why do we care about the eigenvalues of the Frobenius map?

All of the other answers give good reasons why the eigenvalues and their absolute values are important, but it should be noted that the eigenvalues can be used to give an exact point count via the ...
Joe Silverman's user avatar
13 votes

The Weil numbers and modulus of an elliptic curve

If $E$ does not have CM, then $\tau$ will be transcendental over $\mathbb Q$, so it's hard to imagine a relation with the eigenvalues of Frobenius, which are integers in an imaginary quadratic field. ...
Joe Silverman's user avatar
13 votes
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Computing the etale cohomology of spheres

This is true over any algebraically closed field $k$ of characteristic different from $2$. More generally, if $\ell$ is invertible in $k$, then $$H^i(X,\mathbb Z_\ell) = \left\{\begin{array}{ll}\...
R. van Dobben de Bruyn's user avatar
13 votes
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Cohomology of resolution of singularity

In general, the answer is no. It already fails for a nodal curve. In fancier terms, you can understand the obstruction as follows: if $X$ has a resolution $\tilde X$, and the cohomology of $X$ injects ...
Donu Arapura's user avatar
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13 votes
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On the definition of the etale site of an adic space

Great question! The short answer is that Huber simply wanted to be in a setting where everything is (stably) sheafy, and so put some assumptions ensuring this. Note that Huber's work remained somewhat ...
Peter Scholze's user avatar
12 votes

Flat versus etale cohomology

Here is a good example of some pathological behaviour that will shatter all your hopes and dreams. Claim. Let $k$ be a perfect field, and let $X$ be a smooth, proper, integral $k$-scheme. Then the ...
R. van Dobben de Bruyn's user avatar
12 votes
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Complete intersections in toric varieties

Any smooth projective toric variety is rational, in particular simply connected. Then, by the Lefschetz hyperplane theorem for global complete intersections, if $\dim X \geq 3$ is a smooth complete ...
Francesco Polizzi's user avatar
12 votes
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Homology of the étale homotopy type

I'm sure there are easier and better ways to think about this, but here's how I like to think about it. Work on the big pro-etale site on all schemes, which maps to the pro-etale site of a point, $\pi:...
Peter Scholze's user avatar
12 votes
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Does $0\to I\to\mathrm{Gal}_K\to\mathrm{Gal}_k\to 0$ always split?

Good question! Let me try to guess what Gabber had in mind there. (Note that he only says "known" (to him), not "well-known"...) The claim is that the extension splits. Note that ...
Peter Scholze's user avatar
12 votes
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The Mumford-Tate conjecture

Yes. Under the Hodge conjecture, the Hodge cycles are the algebraic cycles, so the $\mathbb Q_\ell$-linear combinations of Hodge cycles are the $\mathbb Q_\ell$-linear combinations of algebraic cycles....
Will Sawin's user avatar
  • 131k

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