16 votes
Accepted

Smooth projective models of Severi-Brauer varieties over a DVR are also Severi-Brauer varieties

I wrote up some notes on this in 2004. There have been some developments since then that I will indicate below. Denote the smooth, proper morphism as follows, $$\pi:\mathcal{X}\to \text{Spec}\ R.$$ ...
12 votes
Accepted

Brauer groups and field extensions

No: the conic $C:X^2+Y^2+1=0$ splits over the field $L=\mathbb{Q}(x)[y]/(x^2+y^2+1)$, since $(X,Y)=(x,y)$ is an $L$-point of $C$. However $L$ has no subfields algebraic over $\mathbb{Q}$ other than $\...
R.P.'s user avatar
  • 4,665
11 votes

Brauer group of a curve over non-algebraically closed field

Just for completeness: The "correct" way to understand the Brauer group of $X$ using its codimension $1$ points is via residue maps. Specifically: Let $X$ be a regular integral noetherian scheme. ...
Daniel Loughran's user avatar
11 votes
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Software for detecting Brauer-Manin obstructions?

I strongly disagree with the assertion that "the language of modern algebraic geometry [...] is unfamiliar to many people who might otherwise have the right skills to write the software". ...
David Loeffler's user avatar
11 votes
Accepted

Brauer group of rational numbers

What reference are you reading? For a field $K$, every finite-dimensional central simple $K$-algebra $A$ is isomorphic to ${\rm M}_n(D)$ where $n$ is a positive integer and $D$ is a division ring with ...
KConrad's user avatar
  • 49.1k
10 votes
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Are local fields $C_{2}$?

No: see Guy Terjanian, "Un contre-example à une conjecture d'Artin", C. R. Acad. Sci. Paris Sér. A–B 262 (1966) A612 for an example of homogeneous form of degree $4$ in $18$ variables over the $2$-...
Gro-Tsen's user avatar
  • 28.7k
10 votes

Some questions on division algebras

Questions 2 and 3 are addressed in section 11 of Auel, Asher; Brussel, Eric; Garibaldi, Skip; Vishne, Uzi, Open problems on central simple algebras., Transform. Groups 16, No. 1, 219-264 (2011). ...
pbelmans's user avatar
  • 1,486
10 votes
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Do $PGL_n$-torsors induce elements of the Brauer group

Your first statement is not quite true. A $\mathrm{PGL}_2$-torsor does indeed give an element of order $2$ in the Brauer group, but there can be elements of order $2$ in the Brauer group of a general ...
Martin Bright's user avatar
10 votes

Brauer group of $\mathbb{Z}_{(p)}$

Lemma. Let $K$ be a number field with ring of integers $\mathcal O_K$, and let $S \subseteq \Omega_K^f$ be a set of finite places of $K$. Then there is a canonical short exact sequence $$0 \to \...
R. van Dobben de Bruyn's user avatar
8 votes
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Making $\mathbb{Q}$-cohomology integral

As Jason Starr remarks in the comments, this answer to a question of his implies the answer to both of my questions is "no." For the latter, one may take: $X=\mathbb{P}^1, \mathcal{L}=\mathcal{O}(1)$...
8 votes

Can base-change be non-surjective on Brauer groups?

For finite fields, the Brauer group is zero ( It comes from Wedderburn's theorem), so the answer is NO. For number fields, the answer is YES. Following RP's question in the comments, I will prove the ...
GreginGre's user avatar
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8 votes
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Brauer group of a curve over non-algebraically closed field

I don't think your map is injective. Here is an attempt at a recipe for constructing a counterexample. The ingredients are a $C_1$-field $F$ of characteristic zero and a smooth projective curve $X_0$...
Martin Bright's user avatar
8 votes

Category of modules over an Azumaya algebra and the Brauer group

$k$-linear cocomplete categories admit a "tensor product over $\text{Mod}(k)$" (thinking of them as module categories over $\text{Mod}(k)$) and the only thing you need to know about it to ...
Qiaochu Yuan's user avatar
7 votes
Accepted

On a morphism from the Brauer group to the Picard group

It seems to me that the involution of $Q \otimes Q$ that exchanges $a \otimes b$ and $b\otimes a$ is inner, which means that the homomorphism you describe should always be trivial. Here is the ...
Angelo's user avatar
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7 votes
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Calculating topological index

The index in this case is $8$. You can see that it divides $8$ as your space $X$ supports a tautological degree $8$ topological Azumaya algebra given by the map $B(SL_8/\mu_2) \rightarrow BPGL_8$. If ...
Benjamin Antieau's user avatar
7 votes

Subspaces of $ A_{n}(\mathbb {Q})$ in which all nonzero matrices are invertible

For a field $\mathbb{F}$, let $\mu_\mathbb{F}(n)$ denote the maximal dimension of a subspace $N\subset A_n(\mathbb{F})$ such that all the nonzero elements of $N$ are invertible. For simplicity, I ...
Robert Bryant's user avatar
6 votes

Is any element in $H^2_{et}(X,\mathcal{O}_X^*)$ locally trivial in the Zariski topology?

An explicit simple counter-example is the following: just take the quaternion algebra $(x,y)$ over $k(x,y)$, where $k$ is a field with $\mathrm{char}(k) \neq 2$. This is non-zero on any open subset of ...
Daniel Loughran's user avatar
6 votes

Explicit examples of Azumaya algebras

Another example I found: if $X=G$ is a linear algebraic group over an algebraically closed field $k$, then every Azumaya algebra is given by a projective representation $$\pi_1G \ \longrightarrow \...
Pulcinella's user avatar
  • 5,278
6 votes
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Purity of Brauer group for stacks

The answer seems to be positive and actually at least in the context of regular (locally) noetherian Deligne--Mumford stacks. (Actually, Artin stack should also be enough as we can compute the Brauer ...
Lennart Meier's user avatar
5 votes
Accepted

Are Azumaya algebras of trivial Brauer class isomorphic to $\mathcal{E}nd(\mathcal{H})$?

The answer is yes and one can take $$\mathcal{H}:=\mathcal{Hom}_{\mathcal{End}(\mathcal G)}(\mathcal F\otimes \mathcal A, \mathcal G).$$ Here, $\mathcal F\otimes \mathcal A$ is viewed as a left $\...
Uriya First's user avatar
  • 2,836
5 votes

On a morphism from the Brauer group to the Picard group

Here is another way to see that the given map should be zero. It corresponds to a map of sheaves of grouplike $\mathbb{E}_\infty$-spaces $K(\mathbb{G}_m,2)\rightarrow K(\mathbb{G}_m,1)$. All such maps ...
Benjamin Antieau's user avatar
4 votes

Brauer group of projective space

Here is a proof that works in all characteristics. The idea comes from Colliot-Thélène ["Formes quadratiques multiplicatives et variétés algébriques: deux compléments", Bull. Soc. Math. France, 108(2)...
Martin Bright's user avatar
4 votes
Accepted

What is known about lower etale cohomology of unirational varieties?

Concerning the $H^2$, for $X$ a smooth projective rationally chain connected variety over an algebraically closed field $k$ and $\ell \in k^\ast$, it follows from Theorem 1.2 in https://arxiv.org/...
Ariyan Javanpeykar's user avatar
4 votes

Postnikov invariants of the Brauer 3-group

Let me see if I understand what Jacob says in the comments. I think his argument can be summarized as: the Brauer 3-group is étale-locally an Eilenberg-MacLane spectrum, hence étale-locally an $\...
Qiaochu Yuan's user avatar
4 votes
Accepted

Cohomological Brauer group vs classical

Briefly, one uses the exact sequence $$ H^{1}(X,GL_{n})\rightarrow H^{1}(X,PGL_{n})\rightarrow H^{2}(X,\mathbb{G}_{m}) $$ (etale cohomology). The set $H^{1}(X,PGL_{n})$ classifies the isomorphism ...
anon's user avatar
  • 184
4 votes

Countably many isomorphism classes of reductive groups over a field with countable Brauer and Witt groups

$\newcommand\kalg{k\textrm-\mathbf{alg}}\newcommand\kalgf{\kalg_\text f}$Welcome new contributor. I am just writing my comment as an answer. Let $k$ be a field and denote by $\kalg$ the category ...
3 votes

Brauer group of a curve over non-algebraically closed field

Here's an explicit example (joint with A. Landesman). Let $k$ be an algebraically closed field of characteristic not $2$ or $3$, and let $X/k$ be a non-supersingular K3 with Neron-Severi rank $\geq 5$....
David Benjamin Lim's user avatar
3 votes

Elementary proof that a central simple algebra over a field having a maximal subfield is a cyclic algebra

The proof uses as an essential ingredient Proposition 2.2.8, which itself relies on Lemma 2.2.9 telling you that the k-algebras in $M_n(k)$ isomorphic to $k^n$ are conjugate to the subalgebra of ...
thierry stulemeijer's user avatar

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