K3 surface minus finite set

Question

Let $S$ be a complex K3 surface, and $P\subset S$ a finite set of points in $S$. It is known that $$H^i(S,\mathbb{Z})\cong H^i(S\setminus P,\mathbb{Z})$$ for $0\le i \le 2$. Then the Euler characteristic computation implies that $b_3(S\setminus P)=|P|$. I want to confirm that $$H^3(S\setminus P,\mathbb{Z}) \cong \mathbb{Z}^{|P|},$$ that is, there is no torsion.