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Topology of cell complexes and manifolds, classification of manifolds (e.g. smoothing, surgery), low dimensional topology (e.g. knot theory, invariants of 4-manifolds), embedding theory, combinatorial and PL topology, geometric group theory, infinite dimensional topology (e.g. Hilbert cube manifolds, theory of retracts).

10 votes
Accepted

The space of contractible loops of a finite dimensional $K(\pi,1)$

The statement is true for a $K(\pi,1)$ but not true for other $X$. Finite dimensionality is not relevant. Here's a sketch: let $X = K(\pi,1)$ and I will assume $X$ has the homotopy type of a CW com …
John Klein's user avatar
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11 votes
Accepted

How does the Framed Function Theorem simplify Cerf Theory?

The framed function theorem tells you that up to "contractible choice" a compact manifold admits a framed function: i.e., a function as you prescribe. Furthermore, a framed function is supposed to giv …
John Klein's user avatar
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11 votes

Intuition behind Alexander duality

Yet another way to get it. Alexander duality is closely related to Poincare duality: suppose we can write $$ S^n = K \cup_A C $$ where $K$ and $C$ are codimension zero compact manifolds with common bo …
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7 votes

Atiyah duality without reference to an embedding

Assume $M$ is a closed, smooth manifold of dimension $n$. Let $\tau^+$ be the fiberwise one point compactification of its tangent bundle. This is a fiberwise $n$-spherical fibration equipped with a p …
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9 votes
Accepted

Atiyah duality without reference to an embedding

Here is another short construction which is much simpler and just takes a few lines. Let $M$ be a closed $n$-manifold. Consider the diagonal $M \to M \times M$. It is an embedding. Take its Pontryagi …
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12 votes

The space of framed functions

Eliashberg once told me that the framed function theorem should be a consequence of his work on wrinkled maps. Igusa and I gave a fairly direct proof that the space of framed functions on the circle …
John Klein's user avatar
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11 votes
Accepted

Linking topological spheres

Let $C = S^3 \setminus A$. Alexander duality says that $$ H_1(C) \cong H^1(A) \cong \Bbb Z\, . $$ Let $\alpha: S^1 \to C$ be any map representing a generator of $H_1(C)$ (every first homology class …
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3 votes
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Wall self-intersection invariant for odd-dimensional manifolds?

I doubt that what you are proposing as the receptacle for the obstruction is the correct abelian group. For one thing, you are not taking into account the involution on the canonical double cover of t …
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5 votes

When does an even-dimensional manifold fiber over an odd-dimensional manifold?

No, I don't believe there's a simple solution. But here's an approach to the problem which indicates how it can be fractured up. Assume $M,N$ are closed and connected. If $f\: M \to N$ is homotopic …
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12 votes
1 answer
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A variant of $\ell^2$-cochains

Suppose $X$ is an infinite countable CW complex which satisfies the following property: for all $k$-cells $e$, the number of $(k+1)$-cells incident to $e$ is at most $c_k$, where the latter is some n …
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6 votes

Searching for an unabridged proof of "The Basic Theorem of Morse Theory"

My recollection is that Milnor's proof gives exactly what you are asking. In fact, see the remark on the bottom of page 17 of his book.
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10 votes

Can we decompose Diff(MxN)?

When $N$ is the circle there's a sort of answer. In fact there's a whole chapter in the book Burghelea, Dan; Lashof, Richard; Rothenberg, Melvin: Groups of automorphisms of manifolds. With an append …
John Klein's user avatar
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6 votes

Can one disjoin any submanifold in $\mathbb R^n$ from itself by a $C^{\infty}$-small isotopy?

There are lots of counter-examples. Here's one: The fibration $\text{SO}(3) \to \text{SO}(4) \to S^3$ splits, since it is the principal bundle of the tangent bundle of $S^3$, and the latter is paral …
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6 votes

Stratification of smooth maps from R^n to R?

It looks to me that what you are really interested in is the Thom-Boardman stratification of the function space. For that I would recommend the well-written, Stable Mappings and Their Singularities b …
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11 votes

topological type of smooth manifolds with prescribed homotopy type and pontryagin class

In the $1$-connected case, one may argue as follows: Let $X$ be a closed $1$-connected smooth $n$-manifold, $n \ge 5$. The theory of the Spivak fibration shows that any homotopy equivalence $f: M^n …
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