Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 11919

Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

17 votes
Accepted

Is there always, for a given prime $p$, a prime $\ell<p$ that is not a quadratic residue mod...

Of course. Take a quadratic nonresidue $1\leq n\leq p-1$, then some prime divisor $\ell$ of $n$ will be a quadratic nonresidue. See this MO question for what is known about number fields.
GH from MO's user avatar
  • 95.7k
3 votes

A difficult proof about integers

There are infinitely many solutions with the prime $p:=5$ (in which case $2p+1=11$ is also prime). It is known that the Pell equation $u^2-55v^2=1$ has infinitely many solutions in positive integers. …
GH from MO's user avatar
  • 95.7k
7 votes

Squares of the form $2^j\cdot 3^k+1$

There are finitely many pairs $(j,k)$, and this follows from results on $S$-unit equations. Moreover, the solutions can be effectively determined. Here is a quick treatment going back to the classical …
GH from MO's user avatar
  • 95.7k
3 votes

When is the sum of two quadratic residues modulo a prime again a quadratic residue?

To complement the answers so far let me show using Gauss sums that the number of solutions of $ ax^2+by^2=c $ in $\mathbb{F}_p$ equals $p-\left(\frac{-ab}{p}\right)$ for any $a,b,c\in\mathbb{F}_p^\tim …
GH from MO's user avatar
  • 95.7k
5 votes
Accepted

Are there lower bounds on the quality of a rational approximation?

Here are some standard facts that you can find in many textbooks, e.g. in Cassels: An introduction to diophantine approximation. There exists an $A>0$ such that $\left|\frac{p}{q}-\xi\right|<\frac{1 …
GH from MO's user avatar
  • 95.7k
16 votes
Accepted

Is there a constant $c>0$, such that every natural number $n>1$ is the sum of primes, each w...

The usual proof of Vinogradov's result can be modified to show that every sufficiently large odd $n$ has $\asymp n^2/(\log n)^3$ representations as a sum of three primes with each prime exceeding $cn$ …
GH from MO's user avatar
  • 95.7k
11 votes
Accepted

Irreducible cubics modulo primes

No. It follows from Chebotarev's density theorem that for any polynomials $p_1,\dots,p_k\in\mathbb{Z}[x]$ there are infinitely many primes that split all these polynomials. Simply, apply this theorem …
GH from MO's user avatar
  • 95.7k
27 votes
Accepted

p^2 dividing n^8-n^4+1

Your conjecture is true in the light of the following statements. Proposition 1. A prime $p$ has the form $x^2+24y^2$ if and only if $p\equiv 1\pmod{24}$. Proposition 2. A prime square $p^2$ divides …
GH from MO's user avatar
  • 95.7k
3 votes
Accepted

Diophantine approximations and quadratic polynomials

I think the answer is no. For example, the Oppenheim conjecture (proved by Margulis in 1987) states that if an indefinite nondegenerate quadratic form has at least 3 variables and it is not proportion …
GH from MO's user avatar
  • 95.7k
3 votes
Accepted

Numbers of a certain form not expressible as squares

I recommend this survey about the solution of Catalan's conjecture. We learn from here that the special case you are considering, namely $x^p-y^q=1$ for $p=2$, was solved by Chao Ko in 1964. In 1976 C …
GH from MO's user avatar
  • 95.7k
8 votes

Proving the Irrationality of this Number

To resonate with Henry Cohn's comment, Schanuel's conjecture implies that the natural logarithms of the primes are algebraically independent over $\mathbb{Q}$. In particular, the statement in the orig …
GH from MO's user avatar
  • 95.7k
3 votes

looking for integer pairs $(a,c)$ such that $4a^2 + 8c^2 - 4c + 1$ is a perfect square

With the substitution $x:=2a$, $y:=4c-1$, $z:=2n+1$ your framed equation becomes $$ 2x^2+y^2-2z^2=-1. $$ Equations of this type are studied thoroughly in Section 13.6 "Representation by Anisotropic Te …
GH from MO's user avatar
  • 95.7k
5 votes

Divisibility in a set

The set $A$ has positive lower density, hence the result follows from the main theorem in this paper of Paul Erdős (the proof takes one page).
GH from MO's user avatar
  • 95.7k
5 votes
Accepted

Possible ratios of Pythagorean fractions

This is a sketch how to decide the question for $\frac{4}{9}$. The question is if there are positive integers $a,b,d,e$ such that $\frac{4}{9}=\frac{a/b}{d/e}$ with $a^2+b^2$ and $d^2+e^2$ squares. D …
GH from MO's user avatar
  • 95.7k
5 votes

Function that gives 1 only when an integer is divisible by another integer

In analytic number theory, this function is usually written as $$ f(a,b):=\frac{1}{b}\sum_{n=1}^b e^{2\pi i na/b}.$$ This works in practice. Added. To respond to Andrej Bauer's comment, "in practice" …
GH from MO's user avatar
  • 95.7k

1
2 3 4 5
33
15 30 50 per page