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9 votes
Accepted

A cup product in Galois cohomology of Elliptic curve

One can use the exact sequence $$ 0 \to E(K)/mE(K) \to H^1(K,E[m]) \to H^1(K,E)[m] \to 0 $$ to define a pairing $$ E(K)/mE(K) \times H^1(K,E)[m] \to H^2(K,\mu_m) $$ by taking $(Q,\xi)$ to $\phi(Q'\cup …
Joe Silverman's user avatar
11 votes

Proof of $V\cong \overline{K} \otimes_{K} V_K$ using $H^1(G_{\overline{K}/K},\operatorname{G...

Here's a sketch of the proof. I encourage you to fill in the details yourself. The definition of $V_K$ is $V_K=H^0(G_{\overline K/K},V)$. The key part of the proof is to show that $V$ has a $\overline …
Joe Silverman's user avatar
5 votes

Forms of algebraic varieties

In case you are interested in seeing a situation where the map is not surjective, consider the set of rational maps of degree $f:\mathbb{P}^1\to\mathbb{P}^1$, modulo the conjugation action of $\phi\in …
Joe Silverman's user avatar
4 votes
Accepted

Triviality of torsors after a field extension of bounded degree

This is not even true for elliptic curves over $\mathbb Q$ or $\mathbb Q_p$. For example, by Tate duality the group $H^1(\mathbb Q_p,E)$ is dual to $E(\mathbb Q_p)$, which is an infinite group. This s …
Joe Silverman's user avatar
4 votes
Accepted

A question on the cohomology of elliptic curves over local fields

By the Kummer sequence, your kernel is isomorphic to $E(K_\nu)/p^nE(K_\nu)$ via the connecting homomorphism. If you also assume that your elliptic curve has good reduction ath $\nu$, then the cocycle …
Joe Silverman's user avatar
3 votes
Accepted

Notation for the restriction map in Galois cohomology

I've seen both $\text{Res}_k^K$ and $\text{Res}_{K/k}$, and similarly for the inflation map if $K/k$ is Galois. More generally, if $\Gamma$ is a group acting on a group $G$ and if $\Lambda\subseteq\Ga …
Joe Silverman's user avatar
15 votes

Galois cohomologies of an elliptic curve

$H^2$ appears quite prominently in the duality theory of elliptic curves. For a local field such as a finite extension of $\mathbb Q_p$, one has $H^2(\text{Gal}(\bar K/K),\bar K^*)=\mathbb Q/\mathbb Z …
Joe Silverman's user avatar