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Nov 10, 2019 at 22:16 vote accept Henri Cohen
Nov 20, 2018 at 15:03 comment added Subhajit Jana A small comment: In fact, the Arthur-Selberg trace formula associated to $G$ is, essentially, equivalent to the Jacquet's relative trace formula associated to $(G\times G, \Delta_G)$, where $\Delta_G\hookrightarrow G\times G$ is the diagonal embedding. So the Arthur-Selberg trace formula can be viewed as a special case of the relative trace formula.
Jul 9, 2018 at 23:45 history edited j.c. CC BY-SA 4.0
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Jul 9, 2018 at 17:15 history answered GH from MO CC BY-SA 4.0