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Jul 17, 2013 at 23:38 history edited Brendan McKay CC BY-SA 3.0
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Jul 17, 2013 at 13:32 comment added verret In the cubic vertex-transitive case and n twice an odd number, it immediately follows from the same paper that you get a polynomial rather than exponential upper bound. For example Corollary 4 yields that, for large enough n, we have |G|<n^2. This is not best possible, but is not far off, at least for some values of n. If you need more precise estimates, I can show you a few more references that deal with this. (By the way, the link in your "added" section has a typo.)
Jul 17, 2013 at 5:30 history edited Brendan McKay CC BY-SA 3.0
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Jul 17, 2013 at 5:19 comment added Brendan McKay @verret: Any idea what the maximum is for transitive cubic graphs of order an odd multiple of 2?
Jul 17, 2013 at 5:18 history edited Brendan McKay CC BY-SA 3.0
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Jul 17, 2013 at 3:53 history edited Brendan McKay CC BY-SA 3.0
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Jul 17, 2013 at 3:42 comment added Brendan McKay Great! I vaguely remembered such a paper but hadn't managed to find it today.
Jul 17, 2013 at 2:54 comment added verret The family of vertex-transitive graphs you have in mind are in fact best possible among large enough cubic vertex-transitive graphs. (n=100 or so should already suffice.) This is shown in the paper : "Bounding the order of the vertex-stabiliser in 3-valent vertex-transitive and 4-valent arc-transitive graphs", arxiv.org/abs/1010.2546. Therefore, a counter-example to your conjecture will necessarily be not vertex-transitive.
Jul 17, 2013 at 1:29 history asked Brendan McKay CC BY-SA 3.0