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Is there anyway to formulate the Alexandrov topology algebraically?

One knows that the Alexandrov topology on a preordered set is the finest topology that induces the same [specialization] preorder on the set. Given this, one finds a one-to-one correspondence between ...
Bastam Tajik's user avatar
2 votes
2 answers
269 views

Topological characterisations of properties of posets

Finite connected partially ordered sets are in bijective correspondence to connected finite topological spaces that satisfy T_0, see for example the Wikipedia article Finite topological space. Here ...
Mare's user avatar
  • 25.4k
2 votes
0 answers
88 views

Can this order relation, defined in terms of all topological spaces, be defined in terms of the reals alone?

Let $K$ be the operator monoid under composition of Kuratowski's $14$ set operators generated by topological closure $k$ and complement $c.$ Kuratowski's 1922 paper gives the poset diagram of the ...
mathematrucker's user avatar
10 votes
0 answers
249 views

Let $X$ be a finite set of $n$ ($>1$) elements and $\tau$ be a topology on $X$ having exactly $m$ elements. Can we give any description of $m$?

Let $X$ be a finite set of $n$ ($>1$) elements and $\tau$ be a topology on $X$ having exactly $m$ elements. Can we give any description of $m$ as it relates to $n$? Obviously $2\le m\le 2^n$ and ...
Sourav Ghosh's user avatar
2 votes
0 answers
59 views

What is known about sublocales defined by regular nuclei?

(For basic terminology, which is supposed to be standard anyway, see this other question, which inspired this one.) I am interested in nuclei $j\colon L\to L$ on a frame $L$ which are regular elements ...
Gro-Tsen's user avatar
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3 votes
1 answer
196 views

Computing the Heyting operation on the frame of nuclei

(The following definitions are meant to be standard and are reproduced for completeness of the question.) A frame is a partially ordered set in which every finite subset has a greatest lower bound (“...
Gro-Tsen's user avatar
  • 28.7k
5 votes
2 answers
475 views

Do germs of open sets around a point form a frame?

Let $X$ be a topological space and $x \in X$ a point. Let $\Omega$ be the set of open sets (viꝫ. the topology) of $X$, and $\Omega_x$ the set of germs around $x$ of open sets, that is, $\Omega_x = \...
Gro-Tsen's user avatar
  • 28.7k
5 votes
1 answer
159 views

Scott topology: Suprema of sequences are topological limits

I read that, with the Scott topology, suprema of sequences are topological limits (See page 1 of this article). Let $(X, \le)$ be a DCPO, and $D$ be a directed subset of $X$. I can easily see that the ...
Bob's user avatar
  • 476
2 votes
0 answers
50 views

Can we decompose an increasing net of functions into two increasing nets with prescribed supports?

Let $K$ be a compact Hausdorff space and let $U,V\subset K$ be open. Let $\left(f_{i}\right)_{i\in I}$ be an increasing net of continuous non-negative functions such that $f_{i}\le 1$ and $f_{i}$ ...
erz's user avatar
  • 5,275
2 votes
0 answers
36 views

Continuous analogue for Szpilrajn Theorem: complete preorder extends a continuous preorder

A corollary of Szpilrahn Theorem states: Any preorder on nonempty $X$ has a complete and transitive extension. I am thinking about the "Szpilrahn Theorem" for continuous preorder on ...
dodo's user avatar
  • 589
0 votes
1 answer
136 views

Partial orders on downward closed sets [closed]

Let $P = (V, \sqsubseteq)$ be a partial order and $\mathfrak{D}(P)$ denote the class of downward-closed subsets of the partial order $P$ (i.e, the class of $A \subseteq V$ such that $y\in A \;\&\; ...
user65526's user avatar
  • 629
3 votes
1 answer
143 views

A closed subset of a Dedekind-complete order has subspace topology equal to order topology

Here's a fairly easy fact from point-set topology that I'm having trouble finding a reference for. Say $X$ is a total order satisfying the least-upper bound property, and $S$ is a closed subset of it....
Harry Altman's user avatar
  • 2,495
1 vote
1 answer
129 views

Density and compactness of Boolean embeddings

Let A and B be Boolean algebras and $h:A\rightarrow B$ a Boolean embedding. If every element of $B$ can be expressed both as a join of meets and as a meet of joins of elements in $h(A)$, then the ...
IJM98's user avatar
  • 261
1 vote
1 answer
140 views

Is the Rudin-Keisler ordering a continuous relation?

If $X, Y$ are topological, and $R\subseteq X\times Y$ we say that $R$ is continuous (from $X$ to $Y$) if for every $V\subseteq Y$ with $V$ open, we have $$R^{-1}(V) = \{u\in U: \exists v\in V:(u,v)\...
Dominic van der Zypen's user avatar
0 votes
1 answer
108 views

Ordering preserved by an inverse frame homomorphism

Recall that a frame homomorphism $h:L\to M$ is called ($L$ and $M$ are frames): Dense if, for any $x ∈ L$, $h(x) = 0$ implies $x = 0$. Codense if, for any $x ∈ L$, $h(x) = 1$ implies $x = 1$. ...
Biller Alberto's user avatar
5 votes
2 answers
364 views

Non-homeomorphic connected $T_2$-spaces with isomorphic topology poset

What are examples of non-homeomorphic connected $T_2$-spaces $(X_i,\tau_i)$ for $i=1,2$ such that the posets $(\tau_1, \subseteq)$ and $(\tau_2,\subseteq)$ are order-isomorphic?
Dominic van der Zypen's user avatar
4 votes
1 answer
226 views

Measurable total order

Under what conditions on a metric space $X$, equipped with the Borel $\sigma$-algebra, does there exist a measurable total ordering of the elements of $X$? By "measurable total ordering" we ...
Aryeh Kontorovich's user avatar
1 vote
2 answers
176 views

Reference request: lower sets of a preorder form a lattice

Consider a set $S$ with a preorder $\preceq$ (a preorder is a reflexive and transitive relation). A lower set $A$ of $S$ is defined as a subset of $S$ such that for all $x \in S$ and $y \in A$, if $...
Artemy's user avatar
  • 610
2 votes
1 answer
180 views

Basis or subbasis for Scott topology

Let $X$ be a partially ordered set. A subset $S\subseteq X$ is called Scott-open if and only if it is: Upward-closed: $x\in S$ and $x\le y$ implies $y\in S$; Inaccessible by directed suprema: if $D\...
geodude's user avatar
  • 2,099
2 votes
1 answer
115 views

Is the Scott topology generated by the ideals as the closed sets?

Let $X$ be a directed-complete partial order, or even a complete lattice. A subset $S\subseteq X$ is called Scott-closed if and only if it is: Downward-closed: $y\in S$ and $x\le y$ implies $x\in S$; ...
geodude's user avatar
  • 2,099
2 votes
1 answer
229 views

Fixed point property and interval topology

Given a poset $(P,\leq)$ the interval topology $\tau_i(P)$ on $P$ is generated by $$\{P\setminus\downarrow x : x\in P\} \cup \{P\setminus\uparrow x : x\in P\},$$ where $\downarrow x = \{y\in P: y\leq ...
Dominic van der Zypen's user avatar
4 votes
1 answer
208 views

Embedding ordinals with the order topology into connected $T_2$-spaces

Is there a limit ordinal $\kappa_0$ with $\kappa_0 \lt 2^{\aleph_0}$ and such that for every limit ordinal $\lambda$ with $\kappa_0\leq \lambda\lt 2^{\aleph_0}$ there is a connected $T_2$-space $X_\...
Dominic van der Zypen's user avatar
1 vote
2 answers
210 views

Can the Boolean Algebra of regular open sets be isomorphic to ${\cal P}(\omega)/(\text{fin})$?

Let $(X,\tau)$ be a topological space. $A\subseteq X$ is said to be regular open if $A = \text{int}(\text{cl}(A))$ and let $\text{RO}(X,\tau)$ denote the collection of regular open sets of $X$. A ...
Dominic van der Zypen's user avatar
-5 votes
1 answer
304 views

Borromean rings, Condorcet's paradox and Quantum chromodynamics [closed]

In https://plus.google.com/108432079989441783124/posts/LHewqvcj5Xo T. Abderrahman explains what Borromean rings are. As I noticed in a comment, the underlying order structure is the same as in ...
Sylvain JULIEN's user avatar
2 votes
1 answer
130 views

Topologically Ordered Families of Disjoint Cantor Sets in $I$?

Suppose that we have an uncountable collection $C_\alpha$ of disjoint Cantor Sets contained in the closed unit interval $I$. Suppose we have ordered the indices $\alpha \in [0,1]$ as well. Then is ...
John Samples's user avatar
4 votes
1 answer
252 views

Order convergence vs topological convergence in partially ordered sets

Short version of the question. If $(P,\leq)$ is a partially ordered set (poset), a topology denoted by $\tau_o(P)$ can be defined (see below). There is also another notion of convergence, called order-...
Dominic van der Zypen's user avatar
5 votes
0 answers
160 views

(When) is the Dedekind-MacNeille completion of a po-set Hausdorff?

Let $X$ be a p.o. Consider the topology on $X$ generated by $$U_{x}^{-}:=X\setminus (x\uparrow),\quad U_{x}^{+}:=X\setminus (x\downarrow), \quad x\in X$$ Throughout this discussion I shall refer to ...
Thomas's user avatar
  • 263
6 votes
0 answers
113 views

Closedness of the partial order in complete Hausdorff semitopological semilattices

First some definitions. A semilattice is a commutative semigroup consisting of idempotents (i.e., elements such that $xx=x$). A typical example of a semilattice is the unit interval endowed with the ...
Taras Banakh's user avatar
  • 40.2k
8 votes
2 answers
204 views

Spaces without maximal homogeneous subspaces

A homogeneous space $(X,\tau)$ is a topological space such that for all $x,y\in X$ there is a homeomorphism $\varphi:X\to X$ such that $\varphi(x)=y$. As a previous question implies, the union of an ...
Dominic van der Zypen's user avatar
9 votes
3 answers
404 views

Does the lattice of all topologies embed into the lattice of $T_1$-topologies?

Let $\kappa$ be an infinite cardinal, and let $\text{Top}(\kappa)$ be the lattice of all topologies on $\kappa$, ordered by $\subseteq$. Let $\text{Top}^{T_1}(\kappa)$ be the lattice of all $T_1$-...
Dominic van der Zypen's user avatar
3 votes
1 answer
143 views

Maximal elements in the partially ordered set of image spaces

If $(X,\tau)$ is a topological space, let $\text{Im}(X)$ denote the collection of subsets $S$ of $X$ such that there is a continuous function $f:X\to X$ with $\text{im}(f) = S$. Is there a space $(X,\...
Dominic van der Zypen's user avatar
3 votes
1 answer
142 views

The Wallman and interval topologies on non-principal ultrafilters with the Rudin-Keisler preorder

If $(P,\leq)$ is a pre-odered set (that is, $\leq$ is a reflexive and transitive relation) and $x\in P$, we set $(\uparrow_{\leq} x) = \{p\in P: p\geq x\}$ and $(\downarrow_{\leq} x) = \{p\in P: p\leq ...
Dominic van der Zypen's user avatar
2 votes
1 answer
158 views

Adjoints of the interval topology functor

Given a poset $(P,\leq)$ the interval topology $\tau_i(P)$ on $P$ is generated by $$\{P\setminus{\downarrow x} : x\in P\} \cup \{P\setminus{\uparrow x} : x\in P\},$$ where $\downarrow x = \{y\in P: y\...
Dominic van der Zypen's user avatar
3 votes
1 answer
113 views

Hausdorff interval topology on distributive lattices

Given a poset $(P,\leq)$ the interval topology $\tau_i(P)$ on $P$ is generated by $$\{P\setminus\downarrow x : x\in P\} \cup \{P\setminus\uparrow x : x\in P\},$$ where $\downarrow x = \{y\in P: y\leq ...
Dominic van der Zypen's user avatar
6 votes
1 answer
151 views

Topologies with no minimal $T_2$ topologies above them

Let $(X,\tau)$ be a topological space. With $T_2(\tau)$ we denote the collection of $T_2$-topologies on $X$ that contain $\tau$. Is there an example of a topology $\tau$ such that the partially ...
Dominic van der Zypen's user avatar
4 votes
1 answer
99 views

Spaces that are invariant under some contractions

Let $(X,\tau)$ be a topological space. If $A\subseteq X$ we define the following equivalence relation on $X$: $$\sim_A = \{(x,y) \in X^2: x=y \text{ or }\{x,y\}\subseteq A \}.$$ Let $(X,\tau)$ be an ...
Dominic van der Zypen's user avatar
3 votes
2 answers
126 views

$T_2$-spaces with order-isomorphic topologies

Suppose $X\neq \emptyset$ is a set. Let $\tau_1, \tau_2$ be Hausdorff topologies on $X$ with the property that the partially ordered sets $(\tau_1,\subseteq)$ and $(\tau_2,\subseteq)$ are order-...
Dominic van der Zypen's user avatar
2 votes
2 answers
223 views

What's "serialization" really called, and is there any theory surrounding it?

Define an operator $\mathop{\vec{\bigcup}}$ as follows: Definition. Whenever $A$ is an $I$-indexed family of sets, where $I$ is a totally-ordered set, we have $$\mathop{\vec{\bigcup}}_{i \in I} A_i ...
goblin GONE's user avatar
  • 3,683
0 votes
1 answer
117 views

Product topology and order convergence topology

Let $(P,\leq)$ be a poset. We define the order convergence topology, denoted by $\tau_o(P)$. By a set filter $\mathcal{F}$ on $P$ we mean a collection of subsets of $P$ such that: $\emptyset \notin \...
Dominic van der Zypen's user avatar
4 votes
1 answer
359 views

$\mathbb{R}$ and the order-convergence topology

On most partially ordered sets, the order-convergence topology (defined below) is often highly disconnected, often even discrete or [extremally disconnected].1 However, the order-convergence ...
Dominic van der Zypen's user avatar
4 votes
0 answers
149 views

Interval topology of the poset of all coverings

Let $(P,\leq)$ be a poset. The interval topology $\tau_i(P)$ on $P$ is generated by $$\{P\setminus\downarrow x : x\in P\} \cup \{P\setminus\uparrow x : x\in P\},$$ where $\downarrow x = \{y\in P: y\...
Dominic van der Zypen's user avatar
19 votes
1 answer
448 views

Large Borel antichains in the Cantor cube?

Let $2^\omega$ be the Cantor cube $\{0,1\}^\omega$, endowed with the standard compact metrizable topology and the standard product measure, called the Haar measure. The Cantor cube is considered as a ...
Taras Banakh's user avatar
  • 40.2k
7 votes
2 answers
890 views

When does Scott topology generated by specialization order induced by a sober space (X,$\tau$) equal the initial topology $\tau$?

Let X be a $T_{0}$ space. The specialization order ≤ on X is that if x is contained in cl{y}, then we call "x≤y". Obviously (X,≤) is a partially ordered set. A sober space is a topological space such ...
Zhenchao Lyu's user avatar
3 votes
1 answer
159 views

Compactification of order-disconnected spaces

A totally order-disconnected space (TOD) is a tuple $(P, \leq, \tau)$ where $(P, \leq)$ is a poset and $(P,\tau)$ is a topological space such that for $x\not\leq y$ in $P$ there is a clopen down-set ...
Dominic van der Zypen's user avatar
1 vote
1 answer
170 views

Interval topology on complete Boolean algebras

Let $(P,\leq)$ be a poset. The interval topology $\tau_i(P)$ on $P$ is generated by $$\{P\setminus\downarrow x : x\in P\} \cup \{P\setminus\uparrow x : x\in P\},$$ where $\downarrow x = \{y\in P: y\...
Dominic van der Zypen's user avatar
2 votes
1 answer
244 views

What lattices are isomorphic to $R^{N}$ for some $N$, equipped with the product order?

What lattices are isomorphic to $\mathbb{R}^{N}$ for some $N\in \mathbb{N}$, equipped with the canonical order? Remark: When I say $\mathbb{R}^N$, I don’t mean it to be a vector space. Instead, I ...
Pedram's user avatar
  • 63
3 votes
0 answers
130 views

Duality for continuous lattices based on [0, 1]

A continuous lattice may be defined as a complete lattice in which arbitrary meets distribute over directed joins. A continuous lattice is naturally regarded as an algebraic structure where the ...
Ronnie's user avatar
  • 133
0 votes
1 answer
159 views

Partially ordered set of compatible topologies

Let $X\neq \emptyset$ be a set and let ${\cal J} \subseteq {\cal P}(X)\setminus\{\emptyset\}$ be a collection of non-empty subsets of $X$. We say that a topology $\tau$ on $X$ is ${\cal J}$-compatible ...
Dominic van der Zypen's user avatar
4 votes
1 answer
212 views

Minimal zero-dimensional Hausdorff spaces

A topological space $(X,\tau)$ is said to be zero-dimensional Hausdorff (zdH) if for $x\neq y\in X$ there is $C\subseteq X$ clopen (closed and open) such that $x\in C$, but $y\notin C$. We say a zdH ...
Dominic van der Zypen's user avatar
3 votes
1 answer
106 views

Topology with no direct lower neighbor

Given any poset $(P,\leq)$ and $x, y\in P$ we set $[x,y] = \{p\in P: x\leq p \leq y\}$. For any set $X$, let $\text{Top}(X)$ denote the set of topologies on $X$. The set $\text{Top}(X)$ is a complete ...
Dominic van der Zypen's user avatar