Questions tagged [profinite-groups]

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Why are free groups residually finite?

Why is it that every nontrivial word in a free group (it's easy to reduce to the case of, say, two generators) has a nontrivial image in some finite group? Equivalently, why is the natural map from a ...
Owen Biesel's user avatar
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38 votes
3 answers
5k views

Why are profinite topologies important?

I hope this is not too vague of a question. Stone duality implies that the category Pro(FinSet) is equivalent to the category of Stone spaces (compact, Hausdorff, totally disconnected, topological ...
Mike Shulman's user avatar
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33 votes
4 answers
5k views

A profinite group which is not its own profinite completion?

Is there a profinite group $G$ which is not its own profinite completion? Surely not, I thought. But upon looking into it, I found that there is a special name given to a $G$ which is its own ...
Giuseppe's user avatar
  • 781
27 votes
1 answer
1k views

Nonabelian topological fundamental group of a conjugate variety

Let $X$ be a pointed algebraic variety over the field of complex numbers $\mathbb{C}$. Let $\pi_1^{\rm top}(X)$ and $\pi_1^{\mathrm{\acute{e}t}}(X)$ denote the topological and the étale fundamental ...
Mikhail Borovoi's user avatar
26 votes
1 answer
2k views

Galois Group as a Sheaf

I've noticed that the Galois groups associated to Galois field extensions $L$ of a given field $K$ seem remarkably like a sheaf, with the field extensions taking the place of open set, and the Galois ...
David Corwin's user avatar
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25 votes
2 answers
2k views

Profinite groups as étale fundamental groups

Does every profinite group arise as the étale fundamental group of a connected scheme? Equivalently, does every Galois category arise as the category of finite étale covers of a connected scheme? ...
Martin Brandenburg's user avatar
23 votes
3 answers
1k views

Is $\widehat{\mathbb{Z}}[[t]]\cong\widehat{\mathbb{Z}}[[\widehat{\mathbb{Z}}]]$?

Let $\widehat{\mathbb{Z}}[[\widehat{\mathbb{Z}}]] := \varprojlim_{n,m}(\mathbb{Z}/n)[x]/(x^m-1)$ be the complete group algebra of the profinite free group of rank 1. In Corollary 5.9.2 of Ribes-...
stupid_question_bot's user avatar
22 votes
4 answers
3k views

Homomorphism from $\hat{\mathbb{Z}}$ to $\mathbb{Z}$

I expect this question has a very simple answer. We all know from primary school that there are no non-trivial continuous homomorphisms from $\hat{\mathbb{Z}}$ to $\mathbb{Z}$. What if we forget ...
Martin Bright's user avatar
21 votes
4 answers
3k views

What is the virtue of profinite groups as mathematical objects?

In my own research I use profinite groups quite frequently (for Galois groups and etale fundamental groups). However my use of them amounts to book-keeping: I only care about finite levels (finite ...
20 votes
2 answers
1k views

Without choice, can every homomorphism from a profinite group to a finite group be continuous?

In ZFC, some homomorphisms from profinite groups to finite groups are discontinuous. For instance, see the examples in this question. However, all three constructions given use consequences of the ...
Will Sawin's user avatar
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20 votes
2 answers
2k views

Is every compact topological ring a profinite ring?

There are a lot of compact (Hausdorff) groups, whereas every compact field is finite. What about rings? Is there a classification theorem for compact rings? If you take a cofiltered limit of finite ...
Gene S. Kopp's user avatar
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18 votes
2 answers
1k views

The Riemann zeta function and Haar measure on the profinite integers

In an answer to a question on MU about the Riemann zeta function, I sketched a proof that the probability distribution on $\mathbb{N}$ which assigns $n$ the probability $$\frac{ \frac{1}{n^s} }{\zeta(...
Qiaochu Yuan's user avatar
17 votes
3 answers
2k views

Finitely generated Galois groups

It is well-known that for a given natural number $n$ there is only finite number of extensions of $\mathbb Q_p$ of degree $n$. This result appears in many introductory books on algebraic number theory....
Andrei Jaikin's user avatar
16 votes
3 answers
682 views

An algebraic approach to the thermodynamic limit $N\rightarrow\infty$?

In physics one studies quite often the thermodynamic limit or what we call the $N\rightarrow \infty$ behavior of a system of $N\rightarrow\infty$ particles. This is of particular relevance in the ...
Juan Bermejo Vega's user avatar
16 votes
0 answers
850 views

Continuous cohomology of a profinite group is not a delta functor

Let $G$ be a profinite group, then there is a general notion of continuous cohomology groups $H^n_{\text{cont}}(G, M)$ for any topological $G$-module $M$ (I require topological $G$-modules to be ...
gdb's user avatar
  • 2,841
15 votes
1 answer
634 views

Linear embeddings of nilpotent pro-$p$ groups

Is it true that every finitely generated (topologically) torsion-free nilpotent pro-$p$ group is isomorphic to a subgroup of $U_d(\mathbb{Z}_p)$, the group of $d\times d$-upper triangular matrices ...
Diego Sulca's user avatar
15 votes
1 answer
2k views

Relations between the cohomology of discrete groups and of profinite groups

Let $G$ be a discrete group and $K$ be the profinite completion of $G$. Let $C_K$ denote the category of contionuous $K$-modules and ${C_K}'$ denotes category of finite continuous $K$-modules. Now for ...
ozheidi's user avatar
  • 229
15 votes
0 answers
452 views

Is the absolute Galois group of the rationals Hopfian?

Is every continuous epimorphism from the absolute Galois group of $\mathbb{Q}$ to itself injective?
Pablo's user avatar
  • 11.2k
14 votes
1 answer
2k views

"Concretely" writing down elements in a free profinite group

Let $r$ be a natural number. The elements of the free group $F_r$ on $r$ generators have a nice concrete description as "words" in the $r$ generators (and their inverses). I'd like to know if there is ...
Akhil Mathew's user avatar
  • 25.1k
13 votes
3 answers
883 views

Example of reflective subcategory of (Groups) whose reflector doesn't preserve finite products

A subcategory $D$ of a category $C$ is called reflective, if the embedding $D \hookrightarrow C$ has a left adjoint $L:C \to D$. The left adjoint $L$ is called the reflector. If the category $C$ is ...
Sergei Ivanov's user avatar
13 votes
1 answer
1k views

Difference between the completed group algebra and the profinite completion of a group ring

Let $G$ be a reasonably nice group, say residually finite if need be. We may consider the group algebra $\mathbb{Z}[G]$. Let $\widehat{\mathbb{Z}[G]} := \varprojlim_I\mathbb{Z}[G]/I$ be the ...
stupid_question_bot's user avatar
13 votes
1 answer
640 views

Avoiding countable subgroups of a group homeomorphic to the Cantor space

Update: Further work with Adam (who answers below) and Piotr led to a rather satisfactory result about the problem that motivated the problem below, see our recent paper The Haar Measure Problem. In ...
Boaz Tsaban's user avatar
  • 2,978
13 votes
0 answers
541 views

Higher-dimensional algebraic subgroups of the proalgebraic Nottingham group?

Let $R$ be a commutative ring, and, for $n\ge0$, ${\mathcal{A}}_n={\mathcal{A}}_n(R)$ the group of series $u(x)=\sum_0^\infty a_jx^{j+1}\in R[[x]]$ for which $a_0\in R^\times$ and $u(x)\equiv x\pmod{x^...
Lubin's user avatar
  • 4,048
12 votes
4 answers
2k views

Elements of infinite order in a profinite group

Say G is a profinite group with elements of arbitrarily large order. Do elements of infinite order exist (A) if we assume G is abelian? (B) in general? A start for (A): we can ask the same question ...
Andrew Critch's user avatar
12 votes
1 answer
759 views

Does a (nice) centerless group always have a centerless profinite completion?

This is an extension of a question I asked here on Math.SE Assume that I have a finitely generated residually finite centerless group $G$. Is it true that the profinite completion $\hat{G}$ also has ...
Santana Afton's user avatar
12 votes
1 answer
419 views

Applications of Lubotzky's linearity theorem?

Lubotzky's theorem is a necessary and sufficient set of conditions for a finitely generated discrete group to be linear, i.e. isomorphic to a subgroup of $GL_n(K)$, where $K$ is a field of ...
Joël's user avatar
  • 25.6k
12 votes
0 answers
365 views

Does each compact topological group admit a discontinuous homomorphism to a Polish group?

A compact topological group $G$ is called Van der Waerden if each homomorphism $h:G\to K$ to a compact topological group is continuous. By a classical result of Van der Waerden (1933) the groups $SO(...
Taras Banakh's user avatar
  • 40.2k
12 votes
0 answers
453 views

A question concerning model theory of groups

Several days ago, Professor Martin Bridson gave a very nice talk in my department. Some questions concerning his talk came into my brain Since I am neither a model theorist nor a algebraist, I am not ...
喻 良's user avatar
  • 4,111
11 votes
2 answers
2k views

Two Definitions of "Character" of topological groups

When I first met the concept of "characters" of topological groups in Pontryagin's book "Topological groups", it was defined as follows: Let $G$ be a topological group. A ...
Hiro's user avatar
  • 945
11 votes
1 answer
899 views

Profinite completion of finitely presented groups

Let $G$ be a finitely presented group, $\widehat{G}$ be the profinite completion of $G$, and $f: G\rightarrow \widehat{G}$ be the natural map. My question is: Is there an example of $G$ for which $\...
Bruno's user avatar
  • 497
11 votes
1 answer
238 views

Are there open subgroups of $SL_2(\widehat{\mathbb{Z}})$ which are $GL_2(\widehat{\mathbb{Z}})$-conjugate, but not $SL_2$-conjugate?

I apologize if this is too obvious, but I figure it must have a quick answer. Are there open subgroups $\Gamma\le SL_2(\widehat{\mathbb{Z}})$ which are conjugate in $GL_2(\widehat{\mathbb{Z}})$, but ...
stupid_question_bot's user avatar
11 votes
1 answer
800 views

Dessins d'enfants and absolute Galois group

I would like to know what is the recent progress about the group homomorphism $$ \mathrm{Gal}(\overline{\mathbf{Q}}/\mathbf{Q})\rightarrow \mathrm{Out}(\hat{F_{2}})$$ $\mathrm{Gal}(\overline{\mathbf{...
Ofra's user avatar
  • 1,603
10 votes
3 answers
782 views

History of profinite groups, when was it first mentioned? What was the original definition?

Searching left me hanging. One of my professors told me the definition using the topological properties was the first one but I cannot find any resources. Is that true? If not, how was it originally ...
Horstenson's user avatar
10 votes
3 answers
1k views

Profinite completion of a semidirect product

If we have two finitely generated residually finite groups $G$ and $H$, is there are relation between the profinite completions $\hat{G},\hat{H}$ and the profinite completion of a semidirect product ...
Mustafa Gokhan Benli's user avatar
10 votes
1 answer
431 views

Does $GL_2(\widehat{\mathbb{Z}})$ contain a dense finitely generated subgroup?

It's well known that $SL_2(\widehat{\mathbb{Z}})$ contains $SL_2(\mathbb{Z})$ as a dense and finitely generated subgroup. However, $GL_2(\mathbb{Z})$ is not dense in $GL_2(\widehat{\mathbb{Z}})$, ...
Will Chen's user avatar
  • 9,918
10 votes
2 answers
768 views

Exotic automorphisms of the fundamental group of a curve?

A while back, Jordan S. Ellenberg brought the following problem to my attention. If $G$ is a residually finite group, let $\widehat G$ be its profinite completion. Let $S$ be a closed surface of ...
Autumn Kent's user avatar
  • 10.5k
10 votes
1 answer
652 views

Homomorphic images of a Cartesian product of finite groups

What can be said about the class of groups which can be represented as a homomorphic image of an (infinite) Cartesian product (=unrestricted direct product) of finite groups? What would be simple ...
Pasha Zusmanovich's user avatar
10 votes
2 answers
381 views

Can a positive measure subset of a free group be nowhere dense?

Let $F$ be a finitely generated free group and let $S \subseteq F$ be a subset for which there is some $\epsilon > 0$ such that for any epimorphism to a finite group $\phi \colon F \to G$ we have ...
Pablo's user avatar
  • 11.2k
10 votes
0 answers
462 views

A uniform bound for a "true" non-congruence subgroup

Before stating my question, let me recall the Congruence Subgroup Property/Problem: Given simply connected absolutely and almost simple algebraic group $G$ with fixed realization as a matrix group one ...
Menny's user avatar
  • 638
9 votes
4 answers
2k views

Topological examples of profinite groups

I am preparing a course on profinite groups, to be delievered to early graduate students. The first part of the course will discuss the equivalent characterizations of profinite groups. I will first ...
candl's user avatar
  • 93
9 votes
2 answers
1k views

When is the profinite completion a pro-$p$ group?

My research area is mainly pro-$p$ groups and profinite groups. However, in the last few year I became also interested in discrete groups. Therefore, it seems to me a natural problem to look for ...
Yiftach Barnea's user avatar
9 votes
0 answers
293 views

Colimit of continuous cohomology over subgroups

Suppose $G$ is a profinite group, in fact in the applications I'm interested in it would be a $p$-adic analytic group similar to $GL_{n}(\mathbb{Z}_{p})$. Say $M$ is a profinite $G$-representation, ...
Piotr Pstrągowski's user avatar
8 votes
5 answers
1k views

Does a group have a unique pro-p topology?

If $G$ is a residually $p$ group and $G_i$ ANY filtration (i.e. $G_i\subset G_{i-1}$ and $\cap G_i=e$) of normal $p$-power index subgroups, is the corresponding filtration the usual pro-$p$ ...
Stefan Friedl's user avatar
8 votes
2 answers
738 views

Avoiding countable subgroups of general uncountable groups

The following problem is a general form of another problem (motivation is available there). Initially, the problems were posted together, but the first one is solved below, a solution that does not ...
Boaz Tsaban's user avatar
  • 2,978
8 votes
3 answers
687 views

Definition of a profinite category

When studying objects like profinite groups, profinite spaces and profinite rings, I have noticed that some properties just remain the same. For example they will always be inductive limits of some ...
Keen's user avatar
  • 201
8 votes
2 answers
618 views

A metabelian quotient of a free group

I don't know much about free groups (excepted the very basics), and the following question may be trivial, although it isn't to me. Let $F$ be a free group with $n$ generators $x_1,\dots,x_n$. ...
Joël's user avatar
  • 25.6k
8 votes
1 answer
590 views

Is there a residually finite non-elementary hyperbolic group whose profinite completion is boundedly generated?

Is there a residually finite hyperbolic group $G$ that is not virtually cyclic, such that there exists finitely many procyclic closed subgroups $C_1, \dots, C_n$ of the profinite completion $\hat{G}$ ...
Pablo's user avatar
  • 11.2k
8 votes
1 answer
454 views

Commutator subgroup of the absolute Galois group - a closed subgroup

Let $K$ be a finite extension of $\mathbb{Q}$. Is it possible that the commutator subgroup of the absolute Galois group of $K$ (considered as an abstract group) is a closed subgroup? This property ...
user avatar
8 votes
1 answer
1k views

index of a closed subgroup of a profinite group

In the book "profinite groups, arithmetic, and geometry" of Shatz, the index $(G:H)$ of a closed subgroup $H$ of a profinite group $G$ is defined to be the supernatural number $lcm\big((G/U):(H/(H\cap ...
safak's user avatar
  • 287
8 votes
1 answer
303 views

Is there a left-orderable profinite group?

Is there a nontrivial profinite group $G$ with a binary transitive relation $<$ such that $x<y$ implies $x\neq y$, and for any different $x,y \in G$ either $x < y$ or $y < x$ and such ...
Pablo's user avatar
  • 11.2k

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