Timeline for Does the continuous image of a disc contain an embedded disc?
Current License: CC BY-SA 4.0
10 events
when toggle format | what | by | license | comment | |
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Nov 12 at 21:47 | vote | accept | M. Winter | ||
Nov 12 at 17:46 | answer | added | Oleg Eroshkin | timeline score: 6 | |
Nov 12 at 2:05 | comment | added | M. Winter | @OlegEroshkin I don't need any projections. Just use that $\mathrm{im}(\psi)\subseteq\mathrm{im}(\phi)$. So whatever dimension $\phi$ "lives in" is forced on $\psi$. And you can choose $\phi$ essentially 3-dimensional. | |
Nov 12 at 2:01 | comment | added | Oleg Eroshkin | I don't follow you. The fact that a projection on $\mathbb{R}^3$ is not injective says nothing about the map to $\mathbb{R}^4$. | |
Nov 12 at 1:25 | comment | added | M. Winter | @Oleg Yes, that should suffice as a counterexample. Thank you. It also yields a counterexample for $n\ge 4$ because we can just make $\phi$ map your counterexample to a 3-dimensional subspace, and since $\psi$ must be contained in $\phi$ we are back at the 3-dimensional problem. | |
Nov 12 at 1:22 | comment | added | Oleg Eroshkin | I missed that your map goes to $\mathbb{R}^n$. The answer is no for $n=3$ - attach a disk (necessary with self-intersections) to a non-trivial knot. I don't know the answer for $n>3$. | |
Nov 12 at 0:50 | comment | added | M. Winter | @ThomasKojar Hm, I do not immediately see the relation of my question to the Schoenflies problem for $n\ge 3$. Can you elaborate? I still think that the horned sphere (even a less wild version) might be a counterexample in 3D. | |
Nov 12 at 0:41 | comment | added | M. Winter | @Oleg For $n=2$ you mean? This seems plausible. I would be most interested in $n=3,4$. | |
Nov 12 at 0:40 | comment | added | Oleg Eroshkin | If I understand you correctly, this is the Schoenflies theorem. | |
Nov 11 at 23:46 | history | asked | M. Winter | CC BY-SA 4.0 |