Let $({\cal C},\otimes)$ be a monoidal category, $X$ an object in ${\cal C}$, and $\Psi:X \otimes X \to X \otimes X$ an isomorphism such that $\Psi$ satisfies the braid relation: $$ (\Psi \otimes \text{id}) \circ (\text{id} \otimes \Psi) \circ (\Psi \otimes \text{id}) = (\text{id} \otimes \Psi) \circ (\Psi \otimes \text{id}) \circ (\text{id} \otimes \Psi). $$ What would one call such an isomorphism? The most obvious suggestion is to call it a braiding for $X$. Might this be taken to imply that $\Psi$ comes from a braiding for the category (which I do not want to assume)?
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1$\begingroup$ I think you can just call it a braiding. You might just add in a disclaimer to say that you are not assuming that the category itself is braided. I don't think I have ever heard another term used for a map satisfying that relation. $\endgroup$– MTSOct 21, 2011 at 16:27
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1$\begingroup$ Are you sure you don't want $\Psi$ to be an automorphism of $X \otimes X$? $\endgroup$– S. Carnahan ♦Oct 21, 2011 at 16:39
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$\begingroup$ Yes, of course. $\endgroup$– Réamonn Ó BuachallaOct 21, 2011 at 17:19
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3$\begingroup$ It is a braiding on the subcategory it generates... $\endgroup$– Noah SnyderOct 21, 2011 at 17:24
1 Answer
Assuming S. Carnahan's surmise in his comment is correct, I believe the correct term for this is "Yang-Baxter" operator in a monoidal category (or, you could call an object $X$ equipped with such an automorphism $R: X \otimes X \to X \otimes X$ a Yang-Baxter object). This terminology is given in the seminal paper on the subject, Braided Tensor Categories by Joyal and Street (Adv. Math. 102, pp. 20-78, 1993).
In particular, as observed by Joyal and Street, the braid category can be characterized as the free (i.e., initial in a 2-categorical sense) monoidal category equipped with a Yang-Baxter object.
Edit: Another reference for this terminology:
- André Joyal and Ross Street, Tortile Yang-Baxter operators in a tensor category, J. Pure Appl. Alg. 71 (1991), 43-51.